Solve 11-(-8x)+3x-(-9)

$$11 - ( - 8 x ) + 3 x - ( - 9 )$$

Evaluate

$$11x+20$$

Solution Steps

The opposite of -8x is 8x.

$$11+8x+3x-\left(-9\right)$$

Combine 8x and 3x to get 11x.

$$11+11x-\left(-9\right)$$

The opposite of -9 is 9.

$$11+11x+9$$

Add 11 and 9 to get 20.

$$20+11x$$

Differentiate w.r.t. x

$$11$$

Steps Using Derivative Rule for Sum

The opposite of -8x is 8x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(11+8x+3x-\left(-9\right))$$

Combine 8x and 3x to get 11x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(11+11x-\left(-9\right))$$

The opposite of -9 is 9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(11+11x+9)$$

Add 11 and 9 to get 20.

$$\frac{\mathrm{d}}{\mathrm{d}x}(20+11x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$11x^{1-1}$$

Subtract 1 from 1.

$$11x^{0}$$

For any term t except 0, t^{0}=1.

$$11\times 1$$

For any term t, t\times 1=t and 1t=t.

$$11$$