Solve 11*73*6-15*53*16-45+50^-3

$$11 \cdot 73 \cdot 6 - 15 \cdot 53 \cdot 16 - 45 + 50 ^ { - 3 }$$

Evaluate

$$-\frac{993374999}{125000}=-7946.999992$$

Solution Steps

Multiply 11 and 73 to get 803.

$$803\times 6-15\times 53\times 16-45+50^{-3}$$

Multiply 803 and 6 to get 4818.

$$4818-15\times 53\times 16-45+50^{-3}$$

Multiply 15 and 53 to get 795.

$$4818-795\times 16-45+50^{-3}$$

Multiply 795 and 16 to get 12720.

$$4818-12720-45+50^{-3}$$

Subtract 12720 from 4818 to get -7902.

$$-7902-45+50^{-3}$$

Subtract 45 from -7902 to get -7947.

$$-7947+50^{-3}$$

Calculate 50 to the power of -3 and get \frac{1}{125000}.

$$-7947+\frac{1}{125000}$$

Add -7947 and \frac{1}{125000} to get -\frac{993374999}{125000}.

$$-\frac{993374999}{125000}$$

Factor

$$-\frac{993374999}{125000} = -7946\frac{124999}{125000} = -7946.999992$$