Solve 10y+5x*10z=105

$$10y+5x \times 10z=105$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{2y-21}{10z}\text{, }&z\neq 0\\x\in \mathrm{R}\text{, }&y=\frac{21}{2}\text{ and }z=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 5 and 10 to get 50.

$$10y+50xz=105$$

Subtract 10y from both sides.

$$50xz=105-10y$$

The equation is in standard form.

$$50zx=105-10y$$

Divide both sides by 50z.

$$\frac{50zx}{50z}=\frac{105-10y}{50z}$$

Dividing by 50z undoes the multiplication by 50z.

$$x=\frac{105-10y}{50z}$$

Divide 105-10y by 50z.

$$x=\frac{21-2y}{10z}$$

Solve for y

$$y=\frac{21}{2}-5xz$$

Steps for Solving Linear Equation

Multiply 5 and 10 to get 50.

$$10y+50xz=105$$

Subtract 50xz from both sides.

$$10y=105-50xz$$

Divide both sides by 10.

$$\frac{10y}{10}=\frac{105-50xz}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$y=\frac{105-50xz}{10}$$

Divide 105-50xz by 10.

$$y=\frac{21}{2}-5xz$$