Solve for x
x=\frac{3y}{y+5}
y\neq -5
Solve for y
y=-\frac{5x}{x-3}
x\neq 3
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\left(10+2y\right)x=6y
Combine all terms containing x.
\left(2y+10\right)x=6y
The equation is in standard form.
\frac{\left(2y+10\right)x}{2y+10}=\frac{6y}{2y+10}
Divide both sides by 10+2y.
x=\frac{6y}{2y+10}
Dividing by 10+2y undoes the multiplication by 10+2y.
x=\frac{3y}{y+5}
Divide 6y by 10+2y.
10x+2xy-6y=0
Subtract 6y from both sides.
2xy-6y=-10x
Subtract 10x from both sides. Anything subtracted from zero gives its negation.
\left(2x-6\right)y=-10x
Combine all terms containing y.
\frac{\left(2x-6\right)y}{2x-6}=-\frac{10x}{2x-6}
Divide both sides by 2x-6.
y=-\frac{10x}{2x-6}
Dividing by 2x-6 undoes the multiplication by 2x-6.
y=-\frac{5x}{x-3}
Divide -10x by 2x-6.
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