Factor
4\left(3a+b\right)\left(9a^{2}-3ab+b^{2}\right)
Evaluate
4\left(27a^{3}+b^{3}\right)
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4\left(27a^{3}+b^{3}\right)
Factor out 4.
\left(3a+b\right)\left(9a^{2}-3ab+b^{2}\right)
Consider 27a^{3}+b^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right).
4\left(3a+b\right)\left(9a^{2}-3ab+b^{2}\right)
Rewrite the complete factored expression.
Examples
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