Solve 10572(1+12/200)1^2

$$10572(1+ \frac{ 12 }{ 200 } ) { 1 }^{ 2 }$$

Evaluate

$$\frac{280158}{25}=11206.32$$

Solution Steps

Reduce the fraction \frac{12}{200} to lowest terms by extracting and canceling out 4.

$$10572\left(1+\frac{3}{50}\right)\times 1^{2}$$

Convert 1 to fraction \frac{50}{50}.

$$10572\left(\frac{50}{50}+\frac{3}{50}\right)\times 1^{2}$$

Since \frac{50}{50} and \frac{3}{50} have the same denominator, add them by adding their numerators.

$$10572\times \frac{50+3}{50}\times 1^{2}$$

Add 50 and 3 to get 53.

$$10572\times \frac{53}{50}\times 1^{2}$$

Express 10572\times \frac{53}{50} as a single fraction.

$$\frac{10572\times 53}{50}\times 1^{2}$$

Multiply 10572 and 53 to get 560316.

$$\frac{560316}{50}\times 1^{2}$$

Reduce the fraction \frac{560316}{50} to lowest terms by extracting and canceling out 2.

$$\frac{280158}{25}\times 1^{2}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{280158}{25}\times 1$$

Multiply \frac{280158}{25} and 1 to get \frac{280158}{25}.

$$\frac{280158}{25}$$

Factor

$$\frac{2 \cdot 3 \cdot 53 \cdot 881}{5 ^ {2}} = 11206\frac{8}{25} = 11206.32$$