Solve for x
x=-\frac{y}{5}-\frac{3z}{1000}+\frac{2001}{1000}
Solve for y
y=-\frac{3z}{200}-5x+\frac{2001}{200}
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1000x+3z=2001-200y
Subtract 200y from both sides.
1000x=2001-200y-3z
Subtract 3z from both sides.
1000x=2001-3z-200y
The equation is in standard form.
\frac{1000x}{1000}=\frac{2001-3z-200y}{1000}
Divide both sides by 1000.
x=\frac{2001-3z-200y}{1000}
Dividing by 1000 undoes the multiplication by 1000.
x=-\frac{y}{5}-\frac{3z}{1000}+\frac{2001}{1000}
Divide 2001-200y-3z by 1000.
200y+3z=2001-1000x
Subtract 1000x from both sides.
200y=2001-1000x-3z
Subtract 3z from both sides.
200y=2001-3z-1000x
The equation is in standard form.
\frac{200y}{200}=\frac{2001-3z-1000x}{200}
Divide both sides by 200.
y=\frac{2001-3z-1000x}{200}
Dividing by 200 undoes the multiplication by 200.
y=-\frac{3z}{200}-5x+\frac{2001}{200}
Divide 2001-1000x-3z by 200.
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