Solve 1000-10x_{1}+20x_{2}quad=800

$$1000 - 10 x _ { 1 } + 20 x _ { 2 } \quad = 800$$

Solve for x_1

$$x_{1}=2\left(x_{2}+10\right)$$

Steps for Solving Linear Equation

Subtract 1000 from both sides.

$$-10x_{1}+20x_{2}=800-1000$$

Subtract 1000 from 800 to get -200.

$$-10x_{1}+20x_{2}=-200$$

Subtract 20x_{2} from both sides.

$$-10x_{1}=-200-20x_{2}$$

The equation is in standard form.

$$-10x_{1}=-20x_{2}-200$$

Divide both sides by -10.

$$\frac{-10x_{1}}{-10}=\frac{-20x_{2}-200}{-10}$$

Dividing by -10 undoes the multiplication by -10.

$$x_{1}=\frac{-20x_{2}-200}{-10}$$

Divide -200-20x_{2} by -10.

$$x_{1}=2x_{2}+20$$

Solve for x_2

$$x_{2}=\frac{x_{1}-20}{2}$$

Steps for Solving Linear Equation

Subtract 1000 from both sides.

$$-10x_{1}+20x_{2}=800-1000$$

Subtract 1000 from 800 to get -200.

$$-10x_{1}+20x_{2}=-200$$

Add 10x_{1} to both sides.

$$20x_{2}=-200+10x_{1}$$

The equation is in standard form.

$$20x_{2}=10x_{1}-200$$

Divide both sides by 20.

$$\frac{20x_{2}}{20}=\frac{10x_{1}-200}{20}$$

Dividing by 20 undoes the multiplication by 20.

$$x_{2}=\frac{10x_{1}-200}{20}$$

Divide -200+10x_{1} by 20.

$$x_{2}=\frac{x_{1}}{2}-10$$