Solve 1000(1+x)^2=12100

$$1000 ( 1 + x ) ^ { 2 } = 12100$$

Solve for x

$$x=\frac{11\sqrt{10}}{10}-1\approx 2.478505426$$

$$x=-\frac{11\sqrt{10}}{10}-1\approx -4.478505426$$

Steps by Finding Square Root

Divide both sides by 1000.

$$\frac{1000\left(x+1\right)^{2}}{1000}=\frac{12100}{1000}$$

Dividing by 1000 undoes the multiplication by 1000.

$$\left(x+1\right)^{2}=\frac{12100}{1000}$$

Reduce the fraction \frac{12100}{1000} to lowest terms by extracting and canceling out 100.

$$\left(x+1\right)^{2}=\frac{121}{10}$$

Take the square root of both sides of the equation.

$$x+1=\frac{11\sqrt{10}}{10} x+1=-\frac{11\sqrt{10}}{10}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{11\sqrt{10}}{10}-1 x+1-1=-\frac{11\sqrt{10}}{10}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{11\sqrt{10}}{10}-1 x=-\frac{11\sqrt{10}}{10}-1$$