Solve 100-x^2=18^2-16^2+32x-x^2

$$100- { x }^{ 2 } = { 18 }^{ 2 } - { 16 }^{ 2 } +32x- { x }^{ 2 }$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Calculate 18 to the power of 2 and get 324.

$$100-x^{2}=324-16^{2}+32x-x^{2}$$

Calculate 16 to the power of 2 and get 256.

$$100-x^{2}=324-256+32x-x^{2}$$

Subtract 256 from 324 to get 68.

$$100-x^{2}=68+32x-x^{2}$$

Subtract 32x from both sides.

$$100-x^{2}-32x=68-x^{2}$$

Add x^{2} to both sides.

$$100-x^{2}-32x+x^{2}=68$$

Combine -x^{2} and x^{2} to get 0.

$$100-32x=68$$

Subtract 100 from both sides.

$$-32x=68-100$$

Subtract 100 from 68 to get -32.

$$-32x=-32$$

Divide both sides by -32.

$$x=\frac{-32}{-32}$$

Divide -32 by -32 to get 1.

$$x=1$$