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\left(10y^{2}-9x\right)\left(10y^{2}+9x\right)
Rewrite 100y^{4}-81x^{2} as \left(10y^{2}\right)^{2}-\left(9x\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(-9x+10y^{2}\right)\left(9x+10y^{2}\right)
Reorder the terms.