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\left(10x^{4}-y^{3}\right)\left(10x^{4}+y^{3}\right)
Rewrite 100x^{8}-y^{6} as \left(10x^{4}\right)^{2}-\left(y^{3}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).