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4\left(25x^{6}-4x^{2}y^{8}\right)
Factor out 4.
x^{2}\left(25x^{4}-4y^{8}\right)
Consider 25x^{6}-4x^{2}y^{8}. Factor out x^{2}.
\left(5x^{2}-2y^{4}\right)\left(5x^{2}+2y^{4}\right)
Consider 25x^{4}-4y^{8}. Rewrite 25x^{4}-4y^{8} as \left(5x^{2}\right)^{2}-\left(2y^{4}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
4x^{2}\left(5x^{2}-2y^{4}\right)\left(5x^{2}+2y^{4}\right)
Rewrite the complete factored expression.