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4\left(25x^{3}-45x^{2}+18x\right)
Factor out 4.
x\left(25x^{2}-45x+18\right)
Consider 25x^{3}-45x^{2}+18x. Factor out x.
a+b=-45 ab=25\times 18=450
Consider 25x^{2}-45x+18. Factor the expression by grouping. First, the expression needs to be rewritten as 25x^{2}+ax+bx+18. To find a and b, set up a system to be solved.
-1,-450 -2,-225 -3,-150 -5,-90 -6,-75 -9,-50 -10,-45 -15,-30 -18,-25
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 450.
-1-450=-451 -2-225=-227 -3-150=-153 -5-90=-95 -6-75=-81 -9-50=-59 -10-45=-55 -15-30=-45 -18-25=-43
Calculate the sum for each pair.
a=-30 b=-15
The solution is the pair that gives sum -45.
\left(25x^{2}-30x\right)+\left(-15x+18\right)
Rewrite 25x^{2}-45x+18 as \left(25x^{2}-30x\right)+\left(-15x+18\right).
5x\left(5x-6\right)-3\left(5x-6\right)
Factor out 5x in the first and -3 in the second group.
\left(5x-6\right)\left(5x-3\right)
Factor out common term 5x-6 by using distributive property.
4x\left(5x-6\right)\left(5x-3\right)
Rewrite the complete factored expression.