Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

100x^{2}+2716x-407405=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-2716±\sqrt{2716^{2}-4\times 100\left(-407405\right)}}{2\times 100}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 100 for a, 2716 for b, and -407405 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-2716±\sqrt{7376656-4\times 100\left(-407405\right)}}{2\times 100}
Square 2716.
x=\frac{-2716±\sqrt{7376656-400\left(-407405\right)}}{2\times 100}
Multiply -4 times 100.
x=\frac{-2716±\sqrt{7376656+162962000}}{2\times 100}
Multiply -400 times -407405.
x=\frac{-2716±\sqrt{170338656}}{2\times 100}
Add 7376656 to 162962000.
x=\frac{-2716±4\sqrt{10646166}}{2\times 100}
Take the square root of 170338656.
x=\frac{-2716±4\sqrt{10646166}}{200}
Multiply 2 times 100.
x=\frac{4\sqrt{10646166}-2716}{200}
Now solve the equation x=\frac{-2716±4\sqrt{10646166}}{200} when ± is plus. Add -2716 to 4\sqrt{10646166}.
x=\frac{\sqrt{10646166}-679}{50}
Divide -2716+4\sqrt{10646166} by 200.
x=\frac{-4\sqrt{10646166}-2716}{200}
Now solve the equation x=\frac{-2716±4\sqrt{10646166}}{200} when ± is minus. Subtract 4\sqrt{10646166} from -2716.
x=\frac{-\sqrt{10646166}-679}{50}
Divide -2716-4\sqrt{10646166} by 200.
x=\frac{\sqrt{10646166}-679}{50} x=\frac{-\sqrt{10646166}-679}{50}
The equation is now solved.
100x^{2}+2716x-407405=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
100x^{2}+2716x-407405-\left(-407405\right)=-\left(-407405\right)
Add 407405 to both sides of the equation.
100x^{2}+2716x=-\left(-407405\right)
Subtracting -407405 from itself leaves 0.
100x^{2}+2716x=407405
Subtract -407405 from 0.
\frac{100x^{2}+2716x}{100}=\frac{407405}{100}
Divide both sides by 100.
x^{2}+\frac{2716}{100}x=\frac{407405}{100}
Dividing by 100 undoes the multiplication by 100.
x^{2}+\frac{679}{25}x=\frac{407405}{100}
Reduce the fraction \frac{2716}{100} to lowest terms by extracting and canceling out 4.
x^{2}+\frac{679}{25}x=\frac{81481}{20}
Reduce the fraction \frac{407405}{100} to lowest terms by extracting and canceling out 5.
x^{2}+\frac{679}{25}x+\left(\frac{679}{50}\right)^{2}=\frac{81481}{20}+\left(\frac{679}{50}\right)^{2}
Divide \frac{679}{25}, the coefficient of the x term, by 2 to get \frac{679}{50}. Then add the square of \frac{679}{50} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+\frac{679}{25}x+\frac{461041}{2500}=\frac{81481}{20}+\frac{461041}{2500}
Square \frac{679}{50} by squaring both the numerator and the denominator of the fraction.
x^{2}+\frac{679}{25}x+\frac{461041}{2500}=\frac{5323083}{1250}
Add \frac{81481}{20} to \frac{461041}{2500} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x+\frac{679}{50}\right)^{2}=\frac{5323083}{1250}
Factor x^{2}+\frac{679}{25}x+\frac{461041}{2500}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{679}{50}\right)^{2}}=\sqrt{\frac{5323083}{1250}}
Take the square root of both sides of the equation.
x+\frac{679}{50}=\frac{\sqrt{10646166}}{50} x+\frac{679}{50}=-\frac{\sqrt{10646166}}{50}
Simplify.
x=\frac{\sqrt{10646166}-679}{50} x=\frac{-\sqrt{10646166}-679}{50}
Subtract \frac{679}{50} from both sides of the equation.
x ^ 2 +\frac{679}{25}x -\frac{81481}{20} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 100
r + s = -\frac{679}{25} rs = -\frac{81481}{20}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{679}{50} - u s = -\frac{679}{50} + u
Two numbers r and s sum up to -\frac{679}{25} exactly when the average of the two numbers is \frac{1}{2}*-\frac{679}{25} = -\frac{679}{50}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{679}{50} - u) (-\frac{679}{50} + u) = -\frac{81481}{20}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{81481}{20}
\frac{461041}{2500} - u^2 = -\frac{81481}{20}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{81481}{20}-\frac{461041}{2500} = \frac{5323083}{1250}
Simplify the expression by subtracting \frac{461041}{2500} on both sides
u^2 = -\frac{5323083}{1250} u = \pm\sqrt{-\frac{5323083}{1250}} = \pm \frac{\sqrt{5323083}}{\sqrt{1250}}i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{679}{50} - \frac{\sqrt{5323083}}{\sqrt{1250}}i = -78.837 s = -\frac{679}{50} + \frac{\sqrt{5323083}}{\sqrt{1250}}i = 51.677
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.