Solve 100-5*{32+(-2)*[18-2*(16-(-2)^4)]}+(-5)^4*(-5)

$$100 - 5 \cdot \{ 32 + ( - 2 ) \cdot [ 18 - 2 \cdot ( 16 - ( - 2 ) ^ { 4 } ) ] \} + ( - 5 ) ^ { 4 } \cdot ( - 5 )$$

Evaluate

$$-3005$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 4 and 1 to get 5.

$$100-5\left(32-2\left(18-2\left(16-\left(-2\right)^{4}\right)\right)\right)+\left(-5\right)^{5}$$

Calculate -2 to the power of 4 and get 16.

$$100-5\left(32-2\left(18-2\left(16-16\right)\right)\right)+\left(-5\right)^{5}$$

Subtract 16 from 16 to get 0.

$$100-5\left(32-2\left(18-2\times 0\right)\right)+\left(-5\right)^{5}$$

Multiply 2 and 0 to get 0.

$$100-5\left(32-2\left(18-0\right)\right)+\left(-5\right)^{5}$$

Subtract 0 from 18 to get 18.

$$100-5\left(32-2\times 18\right)+\left(-5\right)^{5}$$

Multiply -2 and 18 to get -36.

$$100-5\left(32-36\right)+\left(-5\right)^{5}$$

Subtract 36 from 32 to get -4.

$$100-5\left(-4\right)+\left(-5\right)^{5}$$

Multiply 5 and -4 to get -20.

$$100-\left(-20\right)+\left(-5\right)^{5}$$

The opposite of -20 is 20.

$$100+20+\left(-5\right)^{5}$$

Add 100 and 20 to get 120.

$$120+\left(-5\right)^{5}$$

Calculate -5 to the power of 5 and get -3125.

$$120-3125$$

Subtract 3125 from 120 to get -3005.

$$-3005$$

Factor

$$-3005$$