Factor
\frac{\left(40xy^{2}-z^{4}\right)\left(40xy^{2}+z^{4}\right)}{16}
Evaluate
-\frac{z^{8}}{16}+100x^{2}y^{4}
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\frac{1600x^{2}y^{4}-z^{8}}{16}
Factor out \frac{1}{16}.
\left(40xy^{2}-z^{4}\right)\left(40xy^{2}+z^{4}\right)
Consider 1600x^{2}y^{4}-z^{8}. Rewrite 1600x^{2}y^{4}-z^{8} as \left(40xy^{2}\right)^{2}-\left(z^{4}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(40xy^{2}-z^{4}\right)\left(40xy^{2}+z^{4}\right)}{16}
Rewrite the complete factored expression.
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