Solve 100*left(x-1right)^2=81

$$100 \times { \left(x-1 \right) }^{ 2 } =81$$

Solve for x

$$x = \frac{19}{10} = 1\frac{9}{10} = 1.9$$

$$x=\frac{1}{10}=0.1$$

Steps by Finding Square Root

Divide both sides by 100.

$$\frac{100\left(x-1\right)^{2}}{100}=\frac{81}{100}$$

Dividing by 100 undoes the multiplication by 100.

$$\left(x-1\right)^{2}=\frac{81}{100}$$

Take the square root of both sides of the equation.

$$x-1=\frac{9}{10} x-1=-\frac{9}{10}$$

Add 1 to both sides of the equation.

$$x-1-\left(-1\right)=\frac{9}{10}-\left(-1\right) x-1-\left(-1\right)=-\frac{9}{10}-\left(-1\right)$$

Subtracting -1 from itself leaves 0.

$$x=\frac{9}{10}-\left(-1\right) x=-\frac{9}{10}-\left(-1\right)$$

Subtract -1 from \frac{9}{10}.

$$x=\frac{19}{10}$$

Subtract -1 from -\frac{9}{10}.

$$x=\frac{1}{10}$$

The equation is now solved.

$$x=\frac{19}{10} x=\frac{1}{10}$$