Solve 100*500*x+200*50*x-130000x-62500>0

$$100 \cdot 500 \cdot x + 200 \cdot 50 \cdot x - 130000 x - 62500 > 0$$

Solve for x

$$x<-\frac{25}{28}$$

Solution Steps

Multiply 100 and 500 to get 50000. Multiply 200 and 50 to get 10000.

$$50000x+10000x-130000x-62500>0$$

Combine 50000x and 10000x to get 60000x.

$$60000x-130000x-62500>0$$

Combine 60000x and -130000x to get -70000x.

$$-70000x-62500>0$$

Add 62500 to both sides. Anything plus zero gives itself.

$$-70000x>62500$$

Divide both sides by -70000. Since -70000 is negative, the inequality direction is changed.

$$x<\frac{62500}{-70000}$$

Reduce the fraction \frac{62500}{-70000} to lowest terms by extracting and canceling out 2500.

$$x<-\frac{25}{28}$$