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e^{t-8}=100
Swap sides so that all variable terms are on the left hand side.
\log(e^{t-8})=\log(100)
Take the logarithm of both sides of the equation.
\left(t-8\right)\log(e)=\log(100)
The logarithm of a number raised to a power is the power times the logarithm of the number.
t-8=\frac{\log(100)}{\log(e)}
Divide both sides by \log(e).
t-8=\log_{e}\left(100\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
t=2\ln(10)-\left(-8\right)
Add 8 to both sides of the equation.