Solve 10-(-3(x-7)+5x)+40=5(4-3x

$$10-(-3(x-7)+5x)+40=5(4-3x$$

Solve for x

$$x=-\frac{9}{13}\approx -0.692307692$$

Steps for Solving Linear Equation

Use the distributive property to multiply -3 by x-7.

$$10-\left(-3x+21+5x\right)+40=5\left(4-3x\right)$$

Combine -3x and 5x to get 2x.

$$10-\left(2x+21\right)+40=5\left(4-3x\right)$$

To find the opposite of 2x+21, find the opposite of each term.

$$10-2x-21+40=5\left(4-3x\right)$$

Subtract 21 from 10 to get -11.

$$-11-2x+40=5\left(4-3x\right)$$

Add -11 and 40 to get 29.

$$29-2x=5\left(4-3x\right)$$

Use the distributive property to multiply 5 by 4-3x.

$$29-2x=20-15x$$

Add 15x to both sides.

$$29-2x+15x=20$$

Combine -2x and 15x to get 13x.

$$29+13x=20$$

Subtract 29 from both sides.

$$13x=20-29$$

Subtract 29 from 20 to get -9.

$$13x=-9$$

Divide both sides by 13.

$$x=\frac{-9}{13}$$

Fraction \frac{-9}{13} can be rewritten as -\frac{9}{13} by extracting the negative sign.

$$x=-\frac{9}{13}$$