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5z\left(2z^{2}+5\right)-2\left(2z^{2}+5\right)
Do the grouping 10z^{3}+25z-4z^{2}-10=\left(10z^{3}+25z\right)+\left(-4z^{2}-10\right), and factor out 5z in the first and -2 in the second group.
\left(2z^{2}+5\right)\left(5z-2\right)
Factor out common term 2z^{2}+5 by using distributive property. Polynomial 2z^{2}+5 is not factored since it does not have any rational roots.