Solve 10y-5(1+y)=3(2y-2)-20

$$10 y - 5 ( 1 + y ) = 3 ( 2 y - 2 ) - 20$$

Solve for y

$$y=21$$

Steps for Solving Linear Equation

Use the distributive property to multiply -5 by 1+y.

$$10y-5-5y=3\left(2y-2\right)-20$$

Combine 10y and -5y to get 5y.

$$5y-5=3\left(2y-2\right)-20$$

Use the distributive property to multiply 3 by 2y-2.

$$5y-5=6y-6-20$$

Subtract 20 from -6 to get -26.

$$5y-5=6y-26$$

Subtract 6y from both sides.

$$5y-5-6y=-26$$

Combine 5y and -6y to get -y.

$$-y-5=-26$$

Add 5 to both sides.

$$-y=-26+5$$

Add -26 and 5 to get -21.

$$-y=-21$$

Multiply both sides by -1.

$$y=21$$