Solve for x
x\geq \frac{14}{5}
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10x-8\geq 20
Add 6 and 14 to get 20.
10x\geq 20+8
Add 8 to both sides.
10x\geq 28
Add 20 and 8 to get 28.
x\geq \frac{28}{10}
Divide both sides by 10. Since 10 is positive, the inequality direction remains the same.
x\geq \frac{14}{5}
Reduce the fraction \frac{28}{10} to lowest terms by extracting and canceling out 2.
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