Solve for x
x=\frac{3y}{10}+\frac{1}{2}
Solve for y
y=\frac{10x-5}{3}
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10x=5+3y
Add 3y to both sides.
10x=3y+5
The equation is in standard form.
\frac{10x}{10}=\frac{3y+5}{10}
Divide both sides by 10.
x=\frac{3y+5}{10}
Dividing by 10 undoes the multiplication by 10.
x=\frac{3y}{10}+\frac{1}{2}
Divide 5+3y by 10.
-3y=5-10x
Subtract 10x from both sides.
\frac{-3y}{-3}=\frac{5-10x}{-3}
Divide both sides by -3.
y=\frac{5-10x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{10x-5}{3}
Divide 5-10x by -3.
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