Solve 10x-1300+70x+x

$$10 x - 1300 + 70 x + x$$

Evaluate

$$81x-1300$$

Solution Steps

Combine 10x and 70x to get 80x.

$$80x-1300+x$$

Combine 80x and x to get 81x.

$$81x-1300$$

Differentiate w.r.t. x

$$81$$

Steps Using Derivative Rule for Sum

Combine 10x and 70x to get 80x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(80x-1300+x)$$

Combine 80x and x to get 81x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(81x-1300)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$81x^{1-1}$$

Subtract 1 from 1.

$$81x^{0}$$

For any term t except 0, t^{0}=1.

$$81\times 1$$

For any term t, t\times 1=t and 1t=t.

$$81$$