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2\left(5x^{4}-4x^{3}+10x^{2}-8x\right)
Factor out 2.
x\left(5x^{3}-4x^{2}+10x-8\right)
Consider 5x^{4}-4x^{3}+10x^{2}-8x. Factor out x.
x^{2}\left(5x-4\right)+2\left(5x-4\right)
Consider 5x^{3}-4x^{2}+10x-8. Do the grouping 5x^{3}-4x^{2}+10x-8=\left(5x^{3}-4x^{2}\right)+\left(10x-8\right), and factor out x^{2} in the first and 2 in the second group.
\left(5x-4\right)\left(x^{2}+2\right)
Factor out common term 5x-4 by using distributive property.
2x\left(5x-4\right)\left(x^{2}+2\right)
Rewrite the complete factored expression. Polynomial x^{2}+2 is not factored since it does not have any rational roots.