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10x^{4}-3x^{3}-41x^{2}+12x+4=0
To factor the expression, solve the equation where it equals to 0.
±\frac{2}{5},±\frac{4}{5},±2,±4,±\frac{1}{5},±1,±\frac{1}{10},±\frac{1}{2}
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 4 and q divides the leading coefficient 10. List all candidates \frac{p}{q}.
x=2
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
10x^{3}+17x^{2}-7x-2=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide 10x^{4}-3x^{3}-41x^{2}+12x+4 by x-2 to get 10x^{3}+17x^{2}-7x-2. To factor the result, solve the equation where it equals to 0.
±\frac{1}{5},±\frac{2}{5},±1,±2,±\frac{1}{10},±\frac{1}{2}
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -2 and q divides the leading coefficient 10. List all candidates \frac{p}{q}.
x=-2
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
10x^{2}-3x-1=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide 10x^{3}+17x^{2}-7x-2 by x+2 to get 10x^{2}-3x-1. To factor the result, solve the equation where it equals to 0.
x=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}-4\times 10\left(-1\right)}}{2\times 10}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 10 for a, -3 for b, and -1 for c in the quadratic formula.
x=\frac{3±7}{20}
Do the calculations.
x=-\frac{1}{5} x=\frac{1}{2}
Solve the equation 10x^{2}-3x-1=0 when ± is plus and when ± is minus.
\left(x-2\right)\left(2x-1\right)\left(x+2\right)\left(5x+1\right)
Rewrite the factored expression using the obtained roots.