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-24x^{2}-8x+3+19x
Combine 10x^{2} and -34x^{2} to get -24x^{2}.
-24x^{2}+11x+3
Combine -8x and 19x to get 11x.
factor(-24x^{2}-8x+3+19x)
Combine 10x^{2} and -34x^{2} to get -24x^{2}.
factor(-24x^{2}+11x+3)
Combine -8x and 19x to get 11x.
-24x^{2}+11x+3=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-11±\sqrt{11^{2}-4\left(-24\right)\times 3}}{2\left(-24\right)}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-11±\sqrt{121-4\left(-24\right)\times 3}}{2\left(-24\right)}
Square 11.
x=\frac{-11±\sqrt{121+96\times 3}}{2\left(-24\right)}
Multiply -4 times -24.
x=\frac{-11±\sqrt{121+288}}{2\left(-24\right)}
Multiply 96 times 3.
x=\frac{-11±\sqrt{409}}{2\left(-24\right)}
Add 121 to 288.
x=\frac{-11±\sqrt{409}}{-48}
Multiply 2 times -24.
x=\frac{\sqrt{409}-11}{-48}
Now solve the equation x=\frac{-11±\sqrt{409}}{-48} when ± is plus. Add -11 to \sqrt{409}.
x=\frac{11-\sqrt{409}}{48}
Divide -11+\sqrt{409} by -48.
x=\frac{-\sqrt{409}-11}{-48}
Now solve the equation x=\frac{-11±\sqrt{409}}{-48} when ± is minus. Subtract \sqrt{409} from -11.
x=\frac{\sqrt{409}+11}{48}
Divide -11-\sqrt{409} by -48.
-24x^{2}+11x+3=-24\left(x-\frac{11-\sqrt{409}}{48}\right)\left(x-\frac{\sqrt{409}+11}{48}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{11-\sqrt{409}}{48} for x_{1} and \frac{11+\sqrt{409}}{48} for x_{2}.