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10x^{2}=9-2
Subtract 2 from both sides.
10x^{2}=7
Subtract 2 from 9 to get 7.
x^{2}=\frac{7}{10}
Divide both sides by 10.
x=\frac{\sqrt{70}}{10} x=-\frac{\sqrt{70}}{10}
Take the square root of both sides of the equation.
10x^{2}+2-9=0
Subtract 9 from both sides.
10x^{2}-7=0
Subtract 9 from 2 to get -7.
x=\frac{0±\sqrt{0^{2}-4\times 10\left(-7\right)}}{2\times 10}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 10 for a, 0 for b, and -7 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 10\left(-7\right)}}{2\times 10}
Square 0.
x=\frac{0±\sqrt{-40\left(-7\right)}}{2\times 10}
Multiply -4 times 10.
x=\frac{0±\sqrt{280}}{2\times 10}
Multiply -40 times -7.
x=\frac{0±2\sqrt{70}}{2\times 10}
Take the square root of 280.
x=\frac{0±2\sqrt{70}}{20}
Multiply 2 times 10.
x=\frac{\sqrt{70}}{10}
Now solve the equation x=\frac{0±2\sqrt{70}}{20} when ± is plus.
x=-\frac{\sqrt{70}}{10}
Now solve the equation x=\frac{0±2\sqrt{70}}{20} when ± is minus.
x=\frac{\sqrt{70}}{10} x=-\frac{\sqrt{70}}{10}
The equation is now solved.