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10m^{2}-73m=0
Subtract 73m from both sides.
m\left(10m-73\right)=0
Factor out m.
m=0 m=\frac{73}{10}
To find equation solutions, solve m=0 and 10m-73=0.
10m^{2}-73m=0
Subtract 73m from both sides.
m=\frac{-\left(-73\right)±\sqrt{\left(-73\right)^{2}}}{2\times 10}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 10 for a, -73 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
m=\frac{-\left(-73\right)±73}{2\times 10}
Take the square root of \left(-73\right)^{2}.
m=\frac{73±73}{2\times 10}
The opposite of -73 is 73.
m=\frac{73±73}{20}
Multiply 2 times 10.
m=\frac{146}{20}
Now solve the equation m=\frac{73±73}{20} when ± is plus. Add 73 to 73.
m=\frac{73}{10}
Reduce the fraction \frac{146}{20} to lowest terms by extracting and canceling out 2.
m=\frac{0}{20}
Now solve the equation m=\frac{73±73}{20} when ± is minus. Subtract 73 from 73.
m=0
Divide 0 by 20.
m=\frac{73}{10} m=0
The equation is now solved.
10m^{2}-73m=0
Subtract 73m from both sides.
\frac{10m^{2}-73m}{10}=\frac{0}{10}
Divide both sides by 10.
m^{2}-\frac{73}{10}m=\frac{0}{10}
Dividing by 10 undoes the multiplication by 10.
m^{2}-\frac{73}{10}m=0
Divide 0 by 10.
m^{2}-\frac{73}{10}m+\left(-\frac{73}{20}\right)^{2}=\left(-\frac{73}{20}\right)^{2}
Divide -\frac{73}{10}, the coefficient of the x term, by 2 to get -\frac{73}{20}. Then add the square of -\frac{73}{20} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
m^{2}-\frac{73}{10}m+\frac{5329}{400}=\frac{5329}{400}
Square -\frac{73}{20} by squaring both the numerator and the denominator of the fraction.
\left(m-\frac{73}{20}\right)^{2}=\frac{5329}{400}
Factor m^{2}-\frac{73}{10}m+\frac{5329}{400}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(m-\frac{73}{20}\right)^{2}}=\sqrt{\frac{5329}{400}}
Take the square root of both sides of the equation.
m-\frac{73}{20}=\frac{73}{20} m-\frac{73}{20}=-\frac{73}{20}
Simplify.
m=\frac{73}{10} m=0
Add \frac{73}{20} to both sides of the equation.