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k\left(10k+20\right)=0
Factor out k.
k=0 k=-2
To find equation solutions, solve k=0 and 10k+20=0.
10k^{2}+20k=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
k=\frac{-20±\sqrt{20^{2}}}{2\times 10}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 10 for a, 20 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
k=\frac{-20±20}{2\times 10}
Take the square root of 20^{2}.
k=\frac{-20±20}{20}
Multiply 2 times 10.
k=\frac{0}{20}
Now solve the equation k=\frac{-20±20}{20} when ± is plus. Add -20 to 20.
k=0
Divide 0 by 20.
k=-\frac{40}{20}
Now solve the equation k=\frac{-20±20}{20} when ± is minus. Subtract 20 from -20.
k=-2
Divide -40 by 20.
k=0 k=-2
The equation is now solved.
10k^{2}+20k=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{10k^{2}+20k}{10}=\frac{0}{10}
Divide both sides by 10.
k^{2}+\frac{20}{10}k=\frac{0}{10}
Dividing by 10 undoes the multiplication by 10.
k^{2}+2k=\frac{0}{10}
Divide 20 by 10.
k^{2}+2k=0
Divide 0 by 10.
k^{2}+2k+1^{2}=1^{2}
Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
k^{2}+2k+1=1
Square 1.
\left(k+1\right)^{2}=1
Factor k^{2}+2k+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(k+1\right)^{2}}=\sqrt{1}
Take the square root of both sides of the equation.
k+1=1 k+1=-1
Simplify.
k=0 k=-2
Subtract 1 from both sides of the equation.