Solve for c
c=-\frac{3y}{10}-\frac{2}{5}
Solve for y
y=\frac{-10c-4}{3}
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10c=-4-3y
Subtract 3y from both sides.
10c=-3y-4
The equation is in standard form.
\frac{10c}{10}=\frac{-3y-4}{10}
Divide both sides by 10.
c=\frac{-3y-4}{10}
Dividing by 10 undoes the multiplication by 10.
c=-\frac{3y}{10}-\frac{2}{5}
Divide -4-3y by 10.
3y=-4-10c
Subtract 10c from both sides.
3y=-10c-4
The equation is in standard form.
\frac{3y}{3}=\frac{-10c-4}{3}
Divide both sides by 3.
y=\frac{-10c-4}{3}
Dividing by 3 undoes the multiplication by 3.
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