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10\left(b^{3}+64a^{3}\right)
Factor out 10.
\left(4a+b\right)\left(16a^{2}-4ab+b^{2}\right)
Consider b^{3}+64a^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right).
10\left(4a+b\right)\left(16a^{2}-4ab+b^{2}\right)
Rewrite the complete factored expression.