Solve 10Dquad1/4(x+1)=1/5(8

$$10 D \quad \frac { 1 } { 4 } ( x + 1 ) = \frac { 1 } { 5 } ( 8$$

Solve for D

$$D=\frac{16}{25\left(x+1\right)}$$

$$x\neq -1$$

Steps for Solving Linear Equation

Multiply 10 and \frac{1}{4} to get \frac{5}{2}.

$$\frac{5}{2}D\left(x+1\right)=\frac{1}{5}\times 8$$

Use the distributive property to multiply \frac{5}{2}D by x+1.

$$\frac{5}{2}Dx+\frac{5}{2}D=\frac{1}{5}\times 8$$

Multiply \frac{1}{5} and 8 to get \frac{8}{5}.

$$\frac{5}{2}Dx+\frac{5}{2}D=\frac{8}{5}$$

Combine all terms containing D.

$$\left(\frac{5}{2}x+\frac{5}{2}\right)D=\frac{8}{5}$$

The equation is in standard form.

$$\frac{5x+5}{2}D=\frac{8}{5}$$

Divide both sides by \frac{5}{2}x+\frac{5}{2}.

$$\frac{2\times \frac{5x+5}{2}D}{5x+5}=\frac{\frac{8}{5}\times 2}{5x+5}$$

Dividing by \frac{5}{2}x+\frac{5}{2} undoes the multiplication by \frac{5}{2}x+\frac{5}{2}.

$$D=\frac{\frac{8}{5}\times 2}{5x+5}$$

Divide \frac{8}{5} by \frac{5}{2}x+\frac{5}{2}.

$$D=\frac{16}{25\left(x+1\right)}$$

Solve for x

$$x=-1+\frac{16}{25D}$$

$$D\neq 0$$

Steps for Solving Linear Equation

Multiply 10 and \frac{1}{4} to get \frac{5}{2}.

$$\frac{5}{2}D\left(x+1\right)=\frac{1}{5}\times 8$$

Use the distributive property to multiply \frac{5}{2}D by x+1.

$$\frac{5}{2}Dx+\frac{5}{2}D=\frac{1}{5}\times 8$$

Multiply \frac{1}{5} and 8 to get \frac{8}{5}.

$$\frac{5}{2}Dx+\frac{5}{2}D=\frac{8}{5}$$

Subtract \frac{5}{2}D from both sides.

$$\frac{5}{2}Dx=\frac{8}{5}-\frac{5}{2}D$$

The equation is in standard form.

$$\frac{5D}{2}x=-\frac{5D}{2}+\frac{8}{5}$$

Divide both sides by \frac{5}{2}D.

$$\frac{2\times \frac{5D}{2}x}{5D}=\frac{2\left(-\frac{5D}{2}+\frac{8}{5}\right)}{5D}$$

Dividing by \frac{5}{2}D undoes the multiplication by \frac{5}{2}D.

$$x=\frac{2\left(-\frac{5D}{2}+\frac{8}{5}\right)}{5D}$$

Divide \frac{8}{5}-\frac{5D}{2} by \frac{5}{2}D.

$$x=-1+\frac{16}{25D}$$