Solve 10-7div21-18=1

$$10 - 7 \div 21 - 18 = 1$$

Verify

Solution Steps

Reduce the fraction \frac{7}{21} to lowest terms by extracting and canceling out 7.

$$10-\frac{1}{3}-18=1$$

Convert 10 to fraction \frac{30}{3}.

$$\frac{30}{3}-\frac{1}{3}-18=1$$

Since \frac{30}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{30-1}{3}-18=1$$

Subtract 1 from 30 to get 29.

$$\frac{29}{3}-18=1$$

Convert 18 to fraction \frac{54}{3}.

$$\frac{29}{3}-\frac{54}{3}=1$$

Since \frac{29}{3} and \frac{54}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{29-54}{3}=1$$

Subtract 54 from 29 to get -25.

$$-\frac{25}{3}=1$$

Convert 1 to fraction \frac{3}{3}.

$$-\frac{25}{3}=\frac{3}{3}$$

Compare -\frac{25}{3} and \frac{3}{3}.

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