Solve 10-2(12y-3)=2(3y-2)

$$10 - 2 ( 12 y - 3 ) = 2 ( 3 y - 2 )$$

Solve for y

$$y=\frac{2}{3}\approx 0.666666667$$

Steps for Solving Linear Equation

Use the distributive property to multiply -2 by 12y-3.

$$10-24y+6=2\left(3y-2\right)$$

Add 10 and 6 to get 16.

$$16-24y=2\left(3y-2\right)$$

Use the distributive property to multiply 2 by 3y-2.

$$16-24y=6y-4$$

Subtract 6y from both sides.

$$16-24y-6y=-4$$

Combine -24y and -6y to get -30y.

$$16-30y=-4$$

Subtract 16 from both sides.

$$-30y=-4-16$$

Subtract 16 from -4 to get -20.

$$-30y=-20$$

Divide both sides by -30.

$$y=\frac{-20}{-30}$$

Reduce the fraction \frac{-20}{-30} to lowest terms by extracting and canceling out -10.

$$y=\frac{2}{3}$$