Solve 10-5(1+x)/3+3x+1/5=0

$$10 - \frac { 5 ( 1 + x ) } { 3 } + \frac { 3 x + 1 } { 5 } = 0$$

Solve for x

$$x=8$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 15, the least common multiple of 3,5.

$$150-5\times 5\left(1+x\right)+3\left(3x+1\right)=0$$

Multiply -5 and 5 to get -25.

$$150-25\left(1+x\right)+3\left(3x+1\right)=0$$

Use the distributive property to multiply -25 by 1+x.

$$150-25-25x+3\left(3x+1\right)=0$$

Subtract 25 from 150 to get 125.

$$125-25x+3\left(3x+1\right)=0$$

Use the distributive property to multiply 3 by 3x+1.

$$125-25x+9x+3=0$$

Combine -25x and 9x to get -16x.

$$125-16x+3=0$$

Add 125 and 3 to get 128.

$$128-16x=0$$

Subtract 128 from both sides. Anything subtracted from zero gives its negation.

$$-16x=-128$$

Divide both sides by -16.

$$x=\frac{-128}{-16}$$

Divide -128 by -16 to get 8.

$$x=8$$