Solve for x
x=-\frac{y}{40}+\frac{5}{4}
Solve for y
y=50-40x
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8x=10-\frac{1}{5}y
Swap sides so that all variable terms are on the left hand side.
8x=-\frac{y}{5}+10
The equation is in standard form.
\frac{8x}{8}=\frac{-\frac{y}{5}+10}{8}
Divide both sides by 8.
x=\frac{-\frac{y}{5}+10}{8}
Dividing by 8 undoes the multiplication by 8.
x=-\frac{y}{40}+\frac{5}{4}
Divide 10-\frac{y}{5} by 8.
-\frac{1}{5}y=8x-10
Subtract 10 from both sides.
\frac{-\frac{1}{5}y}{-\frac{1}{5}}=\frac{8x-10}{-\frac{1}{5}}
Multiply both sides by -5.
y=\frac{8x-10}{-\frac{1}{5}}
Dividing by -\frac{1}{5} undoes the multiplication by -\frac{1}{5}.
y=50-40x
Divide 8x-10 by -\frac{1}{5} by multiplying 8x-10 by the reciprocal of -\frac{1}{5}.
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