Solve 10-[(7*5)+(40div8)]-(9*5)div(4*2)]

$$10 - [ ( 7 \times 5 ) + ( 40 \div 8 ) ] - ( 9 \times 5 ) \div ( 4 \times 2 ) ]$$

Evaluate

$$-\frac{285}{8}=-35.625$$

Solution Steps

Multiply 7 and 5 to get 35.

$$10-\left(35+\frac{40}{8}\right)-\frac{9\times 5}{4\times 2}$$

Divide 40 by 8 to get 5.

$$10-\left(35+5\right)-\frac{9\times 5}{4\times 2}$$

Add 35 and 5 to get 40.

$$10-40-\frac{9\times 5}{4\times 2}$$

Subtract 40 from 10 to get -30.

$$-30-\frac{9\times 5}{4\times 2}$$

Multiply 9 and 5 to get 45.

$$-30-\frac{45}{4\times 2}$$

Multiply 4 and 2 to get 8.

$$-30-\frac{45}{8}$$

Convert -30 to fraction -\frac{240}{8}.

$$-\frac{240}{8}-\frac{45}{8}$$

Since -\frac{240}{8} and \frac{45}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-240-45}{8}$$

Subtract 45 from -240 to get -285.

$$-\frac{285}{8}$$

Factor

$$-\frac{285}{8} = -35\frac{5}{8} = -35.625$$