Solve 10(x+4)+xgeq13

$$10 ( x + 4 ) + x \geq 13$$

Solve for x

$$x\geq -\frac{27}{11}$$

Solution Steps

Use the distributive property to multiply 10 by x+4.

$$10x+40+x\geq 13$$

Combine 10x and x to get 11x.

$$11x+40\geq 13$$

Subtract 40 from both sides.

$$11x\geq 13-40$$

Subtract 40 from 13 to get -27.

$$11x\geq -27$$

Divide both sides by 11. Since 11 is positive, the inequality direction remains the same.

$$x\geq -\frac{27}{11}$$