Solve 10(2*3^2-3*4+3)+5(-8*2+7)

$$10 ( 2 \cdot 3 ^ { 2 } - 3 \cdot 4 + 3 ) + 5 ( - 8 \cdot 2 + 7 )$$

Evaluate

$$45$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$10\left(2\times 9-3\times 4+3\right)+5\left(-8\times 2+7\right)$$

Multiply 2 and 9 to get 18.

$$10\left(18-3\times 4+3\right)+5\left(-8\times 2+7\right)$$

Multiply 3 and 4 to get 12.

$$10\left(18-12+3\right)+5\left(-8\times 2+7\right)$$

Subtract 12 from 18 to get 6.

$$10\left(6+3\right)+5\left(-8\times 2+7\right)$$

Add 6 and 3 to get 9.

$$10\times 9+5\left(-8\times 2+7\right)$$

Multiply 10 and 9 to get 90.

$$90+5\left(-8\times 2+7\right)$$

Multiply -8 and 2 to get -16.

$$90+5\left(-16+7\right)$$

Add -16 and 7 to get -9.

$$90+5\left(-9\right)$$

Multiply 5 and -9 to get -45.

$$90-45$$

Subtract 45 from 90 to get 45.

$$45$$

Factor

$$3^{2}\times 5$$