Solve for x

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10x^{2}=633-3
Subtract 3 from both sides.
10x^{2}=630
Subtract 3 from 633 to get 630.
x^{2}=\frac{630}{10}
Divide both sides by 10.
x^{2}=63
Divide 630 by 10 to get 63.
x=3\sqrt{7} x=-3\sqrt{7}
Take the square root of both sides of the equation.
10x^{2}+3-633=0
Subtract 633 from both sides.
10x^{2}-630=0
Subtract 633 from 3 to get -630.
x=\frac{0±\sqrt{0^{2}-4\times 10\left(-630\right)}}{2\times 10}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 10 for a, 0 for b, and -630 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 10\left(-630\right)}}{2\times 10}
Square 0.
x=\frac{0±\sqrt{-40\left(-630\right)}}{2\times 10}
Multiply -4 times 10.
x=\frac{0±\sqrt{25200}}{2\times 10}
Multiply -40 times -630.
x=\frac{0±60\sqrt{7}}{2\times 10}
Take the square root of 25200.
x=\frac{0±60\sqrt{7}}{20}
Multiply 2 times 10.
x=3\sqrt{7}
Now solve the equation x=\frac{0±60\sqrt{7}}{20} when ± is plus.
x=-3\sqrt{7}
Now solve the equation x=\frac{0±60\sqrt{7}}{20} when ± is minus.
x=3\sqrt{7} x=-3\sqrt{7}
The equation is now solved.