10 { x }^{ } +12 \leq 2x-4
Solve for x
x\leq -2
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10x+12\leq 2x-4
Calculate x to the power of 1 and get x.
10x+12-2x\leq -4
Subtract 2x from both sides.
8x+12\leq -4
Combine 10x and -2x to get 8x.
8x\leq -4-12
Subtract 12 from both sides.
8x\leq -16
Subtract 12 from -4 to get -16.
x\leq \frac{-16}{8}
Divide both sides by 8. Since 8 is positive, the inequality direction remains the same.
x\leq -2
Divide -16 by 8 to get -2.
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