Solve 10left(1-xright)^2=8.1

$$10 { \left(1-x \right) }^{ 2 } =8.1$$

Solve for x

$$x=0.1$$

$$x=1.9$$

Steps by Finding Square Root

Divide both sides by 10.

$$\frac{10\left(-x+1\right)^{2}}{10}=\frac{8.1}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$\left(-x+1\right)^{2}=\frac{8.1}{10}$$

Divide 8.1 by 10.

$$\left(-x+1\right)^{2}=0.81$$

Take the square root of both sides of the equation.

$$-x+1=\frac{9}{10} -x+1=-\frac{9}{10}$$

Subtract 1 from both sides of the equation.

$$-x+1-1=\frac{9}{10}-1 -x+1-1=-\frac{9}{10}-1$$

Subtracting 1 from itself leaves 0.

$$-x=\frac{9}{10}-1 -x=-\frac{9}{10}-1$$

Subtract 1 from \frac{9}{10}.

$$-x=-\frac{1}{10}$$

Subtract 1 from -\frac{9}{10}.

$$-x=-\frac{19}{10}$$

Divide both sides by -1.

$$\frac{-x}{-1}=-\frac{\frac{1}{10}}{-1} \frac{-x}{-1}=-\frac{\frac{19}{10}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=-\frac{\frac{1}{10}}{-1} x=-\frac{\frac{19}{10}}{-1}$$

Divide -\frac{1}{10} by -1.

$$x=\frac{1}{10}$$

Divide -\frac{19}{10} by -1.

$$x=\frac{19}{10}$$

The equation is now solved.

$$x=\frac{1}{10} x=\frac{19}{10}$$