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100=b^{2}\times 2
Multiply 10 and 10 to get 100.
b^{2}\times 2=100
Swap sides so that all variable terms are on the left hand side.
b^{2}=\frac{100}{2}
Divide both sides by 2.
b^{2}=50
Divide 100 by 2 to get 50.
b=5\sqrt{2} b=-5\sqrt{2}
Take the square root of both sides of the equation.
100=b^{2}\times 2
Multiply 10 and 10 to get 100.
b^{2}\times 2=100
Swap sides so that all variable terms are on the left hand side.
b^{2}\times 2-100=0
Subtract 100 from both sides.
2b^{2}-100=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
b=\frac{0±\sqrt{0^{2}-4\times 2\left(-100\right)}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 0 for b, and -100 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
b=\frac{0±\sqrt{-4\times 2\left(-100\right)}}{2\times 2}
Square 0.
b=\frac{0±\sqrt{-8\left(-100\right)}}{2\times 2}
Multiply -4 times 2.
b=\frac{0±\sqrt{800}}{2\times 2}
Multiply -8 times -100.
b=\frac{0±20\sqrt{2}}{2\times 2}
Take the square root of 800.
b=\frac{0±20\sqrt{2}}{4}
Multiply 2 times 2.
b=5\sqrt{2}
Now solve the equation b=\frac{0±20\sqrt{2}}{4} when ± is plus.
b=-5\sqrt{2}
Now solve the equation b=\frac{0±20\sqrt{2}}{4} when ± is minus.
b=5\sqrt{2} b=-5\sqrt{2}
The equation is now solved.