Solve 10*[(2*4-3)^4+7^0+sqrt[3]{216}]+sqrt{100}=

$$10 \times [ ( 2 \times 4 - 3 ) ^ { 4 } + 7 ^ { 0 } + \sqrt[ 3 ] { 216 } ] + \sqrt { 100 } =$$

Evaluate

$$6330$$

Solution Steps

Multiply 2 and 4 to get 8.

$$10\left(\left(8-3\right)^{4}+7^{0}+\sqrt[3]{216}\right)+\sqrt{100}$$

Subtract 3 from 8 to get 5.

$$10\left(5^{4}+7^{0}+\sqrt[3]{216}\right)+\sqrt{100}$$

Calculate 5 to the power of 4 and get 625.

$$10\left(625+7^{0}+\sqrt[3]{216}\right)+\sqrt{100}$$

Calculate 7 to the power of 0 and get 1.

$$10\left(625+1+\sqrt[3]{216}\right)+\sqrt{100}$$

Add 625 and 1 to get 626.

$$10\left(626+\sqrt[3]{216}\right)+\sqrt{100}$$

Calculate \sqrt[3]{216} and get 6.

$$10\left(626+6\right)+\sqrt{100}$$

Add 626 and 6 to get 632.

$$10\times 632+\sqrt{100}$$

Multiply 10 and 632 to get 6320.

$$6320+\sqrt{100}$$

Calculate the square root of 100 and get 10.

$$6320+10$$

Add 6320 and 10 to get 6330.

$$6330$$

Factor

$$2\times 3\times 5\times 211$$