Solve 10*6div3-4*(-8+3)div7-3+4

$$10 \times 6 \div 3-4 \times (-8+3) \div 7-3+4$$

Evaluate

$$\frac{167}{7}\approx 23.857142857$$

Solution Steps

Multiply 10 and 6 to get 60.

$$\frac{60}{3}-\frac{4\left(-8+3\right)}{7}-3+4$$

Divide 60 by 3 to get 20.

$$20-\frac{4\left(-8+3\right)}{7}-3+4$$

Add -8 and 3 to get -5.

$$20-\frac{4\left(-5\right)}{7}-3+4$$

Multiply 4 and -5 to get -20.

$$20-\frac{-20}{7}-3+4$$

Fraction \frac{-20}{7} can be rewritten as -\frac{20}{7} by extracting the negative sign.

$$20-\left(-\frac{20}{7}\right)-3+4$$

The opposite of -\frac{20}{7} is \frac{20}{7}.

$$20+\frac{20}{7}-3+4$$

Convert 20 to fraction \frac{140}{7}.

$$\frac{140}{7}+\frac{20}{7}-3+4$$

Since \frac{140}{7} and \frac{20}{7} have the same denominator, add them by adding their numerators.

$$\frac{140+20}{7}-3+4$$

Add 140 and 20 to get 160.

$$\frac{160}{7}-3+4$$

Convert 3 to fraction \frac{21}{7}.

$$\frac{160}{7}-\frac{21}{7}+4$$

Since \frac{160}{7} and \frac{21}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{160-21}{7}+4$$

Subtract 21 from 160 to get 139.

$$\frac{139}{7}+4$$

Convert 4 to fraction \frac{28}{7}.

$$\frac{139}{7}+\frac{28}{7}$$

Since \frac{139}{7} and \frac{28}{7} have the same denominator, add them by adding their numerators.

$$\frac{139+28}{7}$$

Add 139 and 28 to get 167.

$$\frac{167}{7}$$

Factor

$$\frac{167}{7} = 23\frac{6}{7} = 23.857142857142858$$