Solve 10*10-5-6div9+left(2^2right)^2

$$10 \times 10-5-6 \div 9+ { \left( { 2 }^{ 2 } \right) }^{ 2 }$$

Evaluate

$$\frac{331}{3}\approx 110.333333333$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$10\times 10-5-\frac{6}{9}+2^{4}$$

Multiply 10 and 10 to get 100.

$$100-5-\frac{6}{9}+2^{4}$$

Subtract 5 from 100 to get 95.

$$95-\frac{6}{9}+2^{4}$$

Reduce the fraction \frac{6}{9} to lowest terms by extracting and canceling out 3.

$$95-\frac{2}{3}+2^{4}$$

Subtract \frac{2}{3} from 95 to get \frac{283}{3}.

$$\frac{283}{3}+2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$\frac{283}{3}+16$$

Add \frac{283}{3} and 16 to get \frac{331}{3}.

$$\frac{331}{3}$$

Factor

$$\frac{331}{3} = 110\frac{1}{3} = 110.33333333333333$$