Solve 10*6/60+10/60x>2

$$10 \times \frac{ 6 }{ 60 } + \frac{ 10 }{ 60 } x > 2$$

Solve for x

$$x>6$$

Solution Steps

Reduce the fraction \frac{6}{60} to lowest terms by extracting and canceling out 6.

$$10\times \frac{1}{10}+\frac{10}{60}x>2$$

Cancel out 10 and 10.

$$1+\frac{10}{60}x>2$$

Reduce the fraction \frac{10}{60} to lowest terms by extracting and canceling out 10.

$$1+\frac{1}{6}x>2$$

Subtract 1 from both sides.

$$\frac{1}{6}x>2-1$$

Subtract 1 from 2 to get 1.

$$\frac{1}{6}x>1$$

Multiply both sides by 6, the reciprocal of \frac{1}{6}. Since \frac{1}{6} is positive, the inequality direction remains the same.

$$x>1\times 6$$

Multiply 1 and 6 to get 6.

$$x>6$$